a stone after falling freely under gravity for 1 second strikes a pane of glass held horizontally. in breaking through the pane , the stone loses half of its velocity.how far will it fall in the next 2 seconf? please important hai
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Answered by
17
30 m will be the answer
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harsneha:
hloooo
Answered by
7
Hi...
According to your question,
u=10m/s
g=10
v=u+get
v=10m/s
After passing through the glass,
u=5m/s
Distance in next 2 seconds
s=ut+1/2gt^2
s=5×2+1/2×10×4
s=30 m
Hope it helps...
According to your question,
u=10m/s
g=10
v=u+get
v=10m/s
After passing through the glass,
u=5m/s
Distance in next 2 seconds
s=ut+1/2gt^2
s=5×2+1/2×10×4
s=30 m
Hope it helps...
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