A stone after projection at an angle 'e' with respect to ground
from roof of a tower, was again at the level of projection two
seconds after the projection and it falls on ground 3 seconds
after the projection. Then height of the tower is (g = 10 m s-2)
Answers
Answered by
1
Answer:Let the Time taken for projectile motion be 'T' and time taken for descend be 't'.
T=
g
2usinθ
=2
usinθ=10
wkt,
s=ut+
2
1
at
2
H=−usinθ×3+
2
1
×10×1
2
H=15m
Explanation:
Answered by
0
Answer:
15m
Explanation:
hope it helps you..........
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