Question

a stone at a height of 5m is thrown horizontally and fall on the ground at a horizontal distance of 10m away from where it was thrown. What is the velocity of the stone at the point of impact with the ground .

Answer 1

time it takes to reach ground from 5m is,
$t=\sqrt(\frac{2h}{g})=\sqrt(10/9.81)=1.01$
by this time, the stone traveled 10m, as gravity has no acceleration component in horizontal direction, we have uniform velocity in horizontal direction! so the thrown velocity is,
$v=\frac{d}{t}=10/1.01=9.9$
which is unaltered in whole of trajectory.
now the velocity in vertical direction is,
$v=gt=9.81*1.01=9.91$
so the total velocity is,
$v=\sqrt(9.9^2+9.91^2)=14.01$
or the velocity is 14 m/s (approximately)

Answer 2

Answer:

the answer u gave is not correct