Question

A stone attached to a string is whirled round in a horizontal circle with a constant speed of 10 m s Calculate the difference in the velocity when the stone is (i) at opposite ends of a diameter and (ii) in two positions A and B where angle AOB is 90 and O is the centre of the circle.

Answer 1

Answer:

Hope it's help you and Mark me as brainliest.

Answer 2

Concept:

• Horizontal uniform circular motion
• Velocity and displacement

Given:

• Constant speed of stone v = 10 m/s

Find:

• The difference in velocity when the stone is at the opposite ends of a diameter
• The difference in velocity in two positions A and B where angle AOB is 90 and O is the centre of the circle

Solution:

• There is only centripetal acceleration and no tangential acceleration. So the speed does not change in magnitude.
• Since the speed is constant throughout the circular motion, the only change is in the direction.
• The speed at the opposite ends of the diameter is the same, 10 m/s, only their directions are opposite
• So the difference in velocity = 10-(-10) = 20 m/s

The difference in velocity is 20 m/s.

#SPJ2