Question

A stone attached to lm' long string
moving with a speed of 5ms / in a circle find the centripetal
acceleration of the stone
​

Answer 1

Answer:

⟹T=F=1.8π² N

Explanation:

Mass, m=0.2 kg

Radius, r=1 m

Angular speed, ω=90 rpm

⟹ω= 60/90

⟹ω=1.5 rps

⟹ω=3π rad/s

(a) Angular velocity, ω=3π rad/s

(b) Centripetal acceleration. a=rw²

⟹a=1×3π×3π

⟹a=9π² m/s²

(c) Centripetal Force, F=ma

⟹F=0.2×9π²

⟹F=1.8π²N

(d) Tension in string, = Centripetal Force

⟹T=F=1.8π²N