Question

A stone drooped into a deep well and is heard to hit the water 3.41s after being dropped.determine the depth of the well

Answer 1

Assume the depth as "h"
Initial velocity(u) = 0
Time(t) = 3.41 sec
Acceleration = g =10m/s^2
Then using the equation of motion
$S=ut+0.5at^2 \\ h = 0+0.5 \times 10 \times 3.41^2 \\ h=58.14m$