Question

A stone dropped freely under gravity from rest. Calculate the distance covered by it in the first two seconds when g=10 m/s^2

Answer 1

h=ut+1/2gt'2
h=0*2+1/2*10*2
h=10m

Answer 2

Given,
u = 0 m/s
t = 2 s
g = 10 m/s2
h = ?
As we know that
h = u*t + 0.5*g*t*t
h = 0*2 + 0.5 * 10* 2 *2
h = 0 + 20
h = 20 m