A stone dropped from a building of height h and it reaches after
1 seconds on earth. From the same building if two stones are
thrown (one upwards and other downwards) with the same velocity
0 and they reach the earth surface after t and 12 seconds
respectively, then
a) t= t1-t2
b) t= t1+t2/2
c) ✓t1t2
d) t= t1^2t2^2
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Answer:
the answer will be t1 =t2
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