Question

A stone dropped from a building of height h and it reaches after t seconds on earth .From the same building if two Stones are thrown (one upward and other downwards) with the same velocity u they reach the earth surface after t1 and t2 seconds respectively ,then prove that t^2=t1+t2?

Answer 1

Answer:

t=√t1t2

Step-by-step explanation:

−h=ut1−12gt21…(i)

h=ut2+12gt22

solving h=12gt1t2…(ii)

For the dropped ball,

h=12gt2…(iii)

From (ii) and (iii)

t=√t1t2