Question

A stone dropped from a building takes 4 seconds to reach the ground. The height of the building is​

Answer 1

Explanation:

initial velocity = 0

time taken = 4s

acceleration = g = 9.8m/s^2

using 2nd equation of motion

s= ut +(1/2)at^2

= (0)(4) +(1/2)(9.8)(4)(4)

= 78.4

So,

distance covered by that stone was 78.4m