A stone dropped from a building top take s 4 sec to reach the ground the height of the building is
Answers
Answered by
3
h=g*t
here, h=?
g=9.8m/s^2
t=4sec
h=(9.8*4)m.
h=39.2m.
here, h=?
g=9.8m/s^2
t=4sec
h=(9.8*4)m.
h=39.2m.
lonely3:
wrong answer correct is 78.4
Answered by
3
Hello friend....!!!
According to the question it is given that,
Time taken by the stone to reach the ground,
t = 4 seconds
H = ?????
According to the equations of motion, we know that
H = ut + 1/2gt^2
H = 0(4) +1/2 (9.8)(4)(4)
H = 78.4 m
____________________
Hope it helps...!!!
According to the question it is given that,
Time taken by the stone to reach the ground,
t = 4 seconds
H = ?????
According to the equations of motion, we know that
H = ut + 1/2gt^2
H = 0(4) +1/2 (9.8)(4)(4)
H = 78.4 m
____________________
Hope it helps...!!!
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