Question

A stone dropped from a height covers 24.5 m in last second of its fall The times of fall is​

Answer 1

Answer:

$44.1m$

Explanation:

Since the stone travels $24.5m$ in the last second of its journey .

$S=ut + \frac{1}{2}at^{2}$

$24.5 = u(1) +\frac{1}{2} (9.8)(1*1)$

$24.5-4.9 = u$

$V^{2} - U^{2} = 2as$

$19.6^{2} -0^{2} =2(9.8)s$

$s=19.6 m$

Total height is $19.6+24.5$

Thus, the height of the tower is $44.1m$

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