Question

A stone dropped from a height of 19.6 metre .calcute.a) time taken to fall on the ground. B) how fast does it move at the end of this fall and
c) accerlation after 1 second​

Answer 1

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s