Question

A stone dropped from a tower reaches the ground in 5s. Calculate the velocity with which it will hit the ground?(g=9.8ms²).
Answer it fast...​

Answer 1

♦ Given:

• Initial velocity = u = 0

• Time = t = 5 s

• Acceleration due to gravity = g = 9.8 m/s²

♣ To find:

➳ Final Velocity = v = ?

♣ Method:

Formula used: v = u + gt

➨ v = 0 + 9.8(5)

➟ v = 0 + 49

➨ v = +49 m/s

Additional information:

1. There are 3 main formulas used in this lesson;

• v = u + at
• S = ut + 1/2 at²
• v² - u² = 2as

Answer 2

Given

A stone dropped from a tower reaches the ground in 5 s

g = 9.8 m/s²

To Find

Velocity with which it will hit the ground

Solution

We know that

$\rm \longrightarrow v=u+gt$

Here

• v = Final velocity
• u = Initial velocity
• g = Accel. due to gravity
• t = Time

According to the question

We must find "v"

Given that

A stone dropped from a tower reaches the ground in 5

g = 9.8 m/s²

Hence

• u = 0 [starts from rest]
• g = 9.8 m/s²
• t = 5 s

Substituting the values

We get

$\rm \longrightarrow v=0+9.8 \times 5 \ m/s$

$\rm \longrightarrow v=9.8 \times 5 \ m/s$

Therefore

$\rm \longrightarrow v=49 \ m/s$

Hence

Velocity with which it will hit the ground = 49 m/s