Question

a stone dropped from a window reaches the ground in 0.5 second first calculate speed just before it hits the ground second what is average speed during 0.5 second third calculate the height of Window from ground

Answer 1

AS WE KNOW
V = U - GT (AS OBJECT IS FALLING)
THEN
V = 0- 10 × 0.5
THEREFORE
V AT JUST BEFORE IT STRIKES THE GROUND
= -5 m/s
NOW AS Vavg = TOTAL DISTANCE / TOTAL TIME
BUT WE DON'T KNOW H (DISTANCE COVERED)
THEN
FROM EQUATION
-H = UT - 1/2 GT
=> H = 1/2 GT
=> H = 5 × (1/2)^2 {0.5 SEC = 1/2 SEC}
H = 5/4
NOW
Vavg = (5/4)/(1/2)
= 5/2
= 5/2 m/s