Physics, asked by abkittiwari2005, 4 months ago

A stone dropped from a window reaches the ground in 0.5 sec.(g=10m/s²) .1) Calculate the speed just before it hits the ground.
2) What is the average speed during 0.5seconds?
3) Calculate the height of window from the ground

Answers

Answered by Atαrαh
4

\bigstar\huge\underline{\mathtt{ Solution:-}}

As per the given question ,

  • Initial velocity = 0 m/s ( as the ball is just dropped )
  • Time taken = 0.5 sec
  • Acceleration due to gravity = 10 m/s ²

As the stone is moving uniformly under the influence of gravity we can use the  kinematic equations in order to solve this question

(1) Speed of the stone just before it hit's the ground

By using the first kinematic equation ,

➽ v = u + at

here ,

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time

➽ v = 0 + 10 x 0.5

➽ v = 5 m/s

The speed of the ball just before it hit's the ground is 5 m/s

2) Height of the window from the ground

By using the second kinematic equation ,

➸ h= ut + gt ²/2

here ,

  • h = height
  • u = initial velocity
  • a = acceleration
  • t = time

➸ h = 0 x 0.5 + 10 x 0.25 /2

➸ h = 5 x 0.25

➸ h = 1.25 m

The height of the window from the ground is 1.25 m

3) Average speed

As per the formula

➺ Average speed = total distance / total time

➺ Average speed = 1.25 / 0.5

➺ Average speed = 2.5 m/s

The average speed during 0.5 s is 2.5 m/s

Answered by BrainlyShadow01
1

\huge\mathcal\color{red} Question

A stone dropped from a window reaches the ground in 0.5 sec.(g=10m/s²) .

1) Calculate the speed just before it hits the ground.

2) What is the average speed during 0.5seconds?

3) Calculate the height of window from the ground.

Given:-

t = 0.5 sec ; a = 10m/s² ; u = 0

\huge\mathcal\color{red} <u>Solution</u>

i. using first law of motion

➣ v = u + at

➣ v = 0 + 10 × 0.5

➣ v = 5m/s

ii. Average Speed

= distance travelled

time taken

Using second law of motion to compute distance travelled.

➣ s = ut + 1/2 at²

➣ s = 1/2 × 10 × 0.5 × 0.5

➣ s = 1.25m

Hence average Speed = 1.25/0.5 => 2.5m/s

iii. Height of stone would be equal to the distance travelled.

And hence, height of stone is 1.25m

✐ Hence Verified

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