A stone dropped from a window reaches the ground in 5 second. Calculate the speed just before it hits the ground
What is the average speed at t = 0.5 second
Calculate the height of window from the ground
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Here,
Initial speed, u = 0
Acceleration, a = 9.8 m/s2
Time, t = 0.5 s
(i)
Using, v = u + at
=> v = 0 + (9.8)(0.5)
=> v = 4.9 m/s
This is the speed when the stone reaches the ground.
(ii)
Distance traveled, s = ut + ½ at2
=> s = 0 + ½ (9.8)(0.5)2
=> s = 1.225 m
So, average speed = 1.225/0.5 = 2.45 m/s
(iii)
Height of window from the ground is 1.225 m
please mark as brainliest if it helps
Initial speed, u = 0
Acceleration, a = 9.8 m/s2
Time, t = 0.5 s
(i)
Using, v = u + at
=> v = 0 + (9.8)(0.5)
=> v = 4.9 m/s
This is the speed when the stone reaches the ground.
(ii)
Distance traveled, s = ut + ½ at2
=> s = 0 + ½ (9.8)(0.5)2
=> s = 1.225 m
So, average speed = 1.225/0.5 = 2.45 m/s
(iii)
Height of window from the ground is 1.225 m
please mark as brainliest if it helps
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