Question

A stone dropped from the building takes 10 s to reach the ground. The velocity with which it hits the ground is what​

Answer 1

Given :-

• initial velocity, u = 0 m/s (rest)
• time, t = 10 sec
• gravitational acceleration,g = 9.8 m/s²

To Find :-

• finaly velocity, v ?

Solution :-

we know by Newton's first equation for gravitation,

$\boxed{ \bold{gt = v - u}}$

$\bold{: \implies 9.8 \times 10 = v - 0 } \\ \\ \bold{: \implies 98 = v } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{: \implies v = 98 \: {m \: s}^{ - 1} } \: \: \: \: \: \: \: \:$

so, the velocity with which the stone hits the ground is 98 m/s