Question

a stone dropped from the edge of a 4.9m high roof find out the following a) time taken to fall 4.9m b) velocity just before it reaches the ground c) what is the acceleration after 1s or 2s from start

Answer 1

time taken to fall 4.9 m =
$\sqrt{2h \div g}$
=
$\sqrt{2 \times 4.9 \div 9.8}$
=1 second



velocity just before reaching the ground = 4.9m/s
acceleration after 1 and 2 second = 9.8m /s ^2