Question

a stone dropped from the height h reaches the earth surface in 1 sec if the same stone is taken to moon and dropped freely from the same height then it will reach the surface of the moon in a time of

Answer 1

Answer:

Assume height is h . Since

$s= ut + \frac{1}{2} g {t}^{2}$

s= h ,u = 0 , t = 1s and a = g

So

$h = 0(t) + \frac{1}{2} g {1}^{2} = \frac{g}{2}$

Now at moon a = g/6 , so

$h = \frac{g}{2} = \frac{1}{2} ( \frac{g}{6}) {t}^{2} \\ \\ {t}^{2} = 6 \\ \\ \red {\boxed{t = \sqrt{6} }}$