Question

A stone dropped from the the top of the tower touches ground in 4 seconds. The hight of the tower is (g=10ms*-2)

Answer 1

Answer:

80

Explanation:

please mark as brain list

Answer 2

The height of the tower is 80 m.

Given that,

Initial speed of the stone, u = 0 m/s

Time taken by the stone to reach the ground, t = 4s

Height of the tower, $H = ut + \frac{1}{2} at^2$

∴ H = $0 + \frac{1}{2} * 10 * 4^2$

  H = 80 m

• The distance is more than or equal to the displacement's magnitude.
• The pace at which a displacement changes over time is referred to as velocity.
• It has m/s units and is a vector quantity.
• The direction of a velocity vector coincides with the body's motion at that precise moment.
• The magnitude of the instantaneous velocity is equal to the current speed.
• The velocity change divided by the time interval is the average acceleration.
• In the same way, as velocity vs. time graphs reveal an object's displacement, acceleration vs. time graphs reveal an object's velocity.
• The area under the graph for a given time interval is equal to the change in velocity for the same time interval.

#SPJ3