Question

A stone dropped from the top of a
tower covers 24.5m in the last
second of its fall. the height of
the tower is​

Answer 1

Answer:

It is given that distance travelled by stone in last second = 24.5 m  

let the height of tower = h

Sn = u + 1/2a(2n-1)  

24.5 = 0 + 10/2(2n-1)

24.5 = 5(2n-1)  

24.5 = 10n - 5  

19.5 = 10n  

1.95 = n  

distance travelled in last second is 1.95  

But distance travelled in (n-1) th second  

(Sn) = u + 1/2g(2n-1)

Sn =  5 [ 2(n-1) -1]

Sn =  5 [ 2n -2 -1 ]  

Sn = 5 [ 2n - 3 ]  

Sn = 10n - 15

Sn = 10n - 15  

24.5 = 10n -15

9.5/10 = 0.95  

total time taken = 1.95 + 0.95 = 2.9 seconds  

height of tower  

1/2gt²

5(2.9)²

5 * 8.41 = 42.5 m

Explanation:

Answer 2

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