Question

A stone dropped from the top of a tower is found to travel 5/9of the hight of the tower during the last secobd of its fall .the time of fall is

Answer 1

Let the height of tower be x
u = 0m/s

So, let time to cover 5/9x of building be t sec

So, time taken to cover 4x/9 of the building = t - 1 sec

5x/9= 5(2t - 1) ...........(i)  g = 10

So,

Again s = ut +1/2gt²
4x/9 = 0 + 5(t - 1)² ..................(ii)
 
Dividing i and ii
 
5x/9/4x/9  =5(2t - 1) /5(t - 1)²
⇒5t² +5 - 10t = 8t - 4
⇒5t² -18t +9 =0

Solving t we get,

t = 3 sec and 0.6 sec

Answer 2

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