Question

A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s–1? (g= 9.8 m s–2)​

Answer 1

Explanation:

Height of the tower, s = 300 m

Initial velocity of the stone, u = 0

Acceleration, a = g = 9.8 m/s2

Speed of sound in air = 340 m/s

The time (t1) taken by the stone to strike the water in the pond can be calculated using the second equation of motion, as:

s = ut1 + 1/2 gt12

300 = 0 + 1/2 × 9.8 × t12

∴ t1 = √300 × 2/9.8 = 7.82 s

Time taken by the sound to reach the top of the tower, t2 = 300/340 = 0.88 s

Therefore, the time after which splash is heard, t = t1 + t2

= 7.82 + 0.88 = 8.7 s.

Answer 2

Answer:

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