a stone dropped from the top of a tower reaches the ground in 8 second equal to 10 metre per second square calculate the distance travelled by the stone in the 8th second
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Step-by-step explanation:
S=ut+1/2×g(2n-1) by using this formula
U=0 since it is dropped from tower
G=10m/s^2
N=8
S=distance i.e.height
S=1/2×10×(2×8-1) =5×15=125m
Answered by
2
Answer:
Step-by-step explanation:
In this case
u=0
a=10
t=8s
S= ut + 1/2at^2
S=0×8+1/2×10×8×8
S=0+5×8×8
S=320m
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