A stone, dropped from the top of a
tower, travels 35 m in the last second
of its journey. The height of the tower
is: (g = 10 m/s)
Answers
Answered by
2
Answer: 45m
Explanation: See the picture
Attachments:
Answered by
10
Answer:
Height of the tower is 80 m
Explanation:
let the time taken by the stone to reach the ground be n sec
so dist travelled in last sec is given by
s=u+a/2(2n-1)
so 35=0+10/2(2n-1)
7=2n-1
n=4sec , so
height of the tower=0+10/2*4x^{2}
height of the tower =16*5=80m
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