Question

A stone dropped from the top of a tree covers 6m height in last 0.2 s of fall . Find height of tree

Answer 1

Let it will take T time to cover the whole length

so we can say

$H = \frac{1}{2}gT^2$

now in last 0.2 s it will cover 6 m

$H - 6 = \frac{1}{2}g(T - 0.2)^2$

now by above two equations

$\frac{1}{2}gT^2 - 6 = \frac{1}{2}g(T-2)^2$

$\frac{1}{2}g(2T - 2)(2) = 6$

$T = 1.3 s$

now the height of the tree is

$H = \frac{1}{2}*10*1.3^2$

$H = 8.45 m$

Answer 2

Answer:

Explanation:

Ans =48.05 metres