Question

A stone dropped from the top of the tower take 5 seconds to reach ground.calculate the velocity of the stone on reaching the ground

Answer 1

HEY FRIEND...!!!
♥HERE IS YOUR ANSWER♥
We know from Kinematics laws that
v = u+at
So here in the given question
$a = g = 9.8 \: or \: 10m {s}^{ - 2} \\ as \: the \: stone \: is \: dropped \: u = 0 \\ so \: we \: get \: that \: v = 5(9.8) = 49m {s}^{ - 1} \\ or \: if \: g \: = 10m {s}^{ - 2} \\ then \: v = 5(10) = 50m {s}^{ - 1}$
I HOPE IT HELPS YOU...!!!

Answer 2

Ola frnd

♥HERE IS YOUR ANSWER♥

We know from Kinematics laws that

v = u+at

So here in the given question

a = g = 9.8 \: or \: 10m {s}^{ - 2} \\ as \: the \: stone \: is \: dropped \: u = 0 \\ so \: we \: get \: that \: v = 5(9.8) = 49m {s}^{ - 1} \\ or \: if \: g \: = 10m {s}^{ - 2} \\ then \: v = 5(10) = 50m {s}^{ - 1}

I HOPE IT HELPS YOU...!!!