A stone dropped from top of a wall reaches the surfaces of water in 2seconds.Find the velocity of the stone while it touches the deapth of the water surface from the top of the wall.
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Answer:
Given :
t = 2s
u = 0
a = 9.8 m/s²
s = ?
s = ut + ½ at²
s = 0 × 2 + ½ × 9.8 × (2)²
s = ½ × 9.8 × 2 × 7
s = 19.6m
Velocity = Displacement/Time
velocity = 19.6/2
velocity = 9.8m/s
Hope it helps
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