A stone dropped from top of a well reaches the surface of water in 2 secon
ds ,find the velocity of stone while it touches the surface of water and what is the Depth of the water surface in the well (g=10m/s square)(using v=u+at,s=ut+1/2at square)
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Answer:
20m
Explanation:
as v= 0+ 10×2=20m and s= 0×2+0.5×10×4=20m
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