Question

A stone dropped from top of a well reaches the surface of water in 2 seconds find the velocity of stone while it toughes the surface of water and what is the depth of water surface from top of a well​

Answer 1

Answer:

velocity of the stone = 20 m/s

Height = 20 meter

Step by step explanations :

Given,

Initial velocity of stone(u) = 0 m/s

time taken to reach water surface = 2 s

let the velocity of the stone by touching the water surface be v

now, m/s²

by the gravitational equation of motion,

v = u + gt

g = gravitational acceleration = 10 m/s²

putting values,

v = 0 + 10(2)

v = 20 m/s

so,

final velocity of stone = 20 m/s

Now,

h = ut + ½ gt²

where,

h = height of stone from water surface

so,

h = 0(2) + ½ × 10 × 2 × 2

h = 20 m

so,

Height = 20 meter