Question

A stone dropped from top of tower of height 300 m high splashes into water off. near base of our when is the splash pad at the top given speed of sound in air is 340 m per second

Answer 1

Height of the tower, s = 300 m
Initial velocity of the stone, u = 0
Acceleration, a = g = 9.8 m/s2
Speed of sound in air = 340 m/s
The time (t1) taken by the stone to strike the water in the pond can be calculated using the second equation of motion, as:
s = ut1 + 1/2 gt12
300 = 0 + 1/2 × 9.8 × t12
∴ t1 = √300 × 2/9.8  = 7.82 s
Time taken by the sound to reach the top of the tower, t2 = 300/340 = 0.88 s
Therefore, the time after which splash is heard,  t = t1 + t2
= 7.82 + 0.88 = 8.7 s.