Question

a stone dropped into a well in which the leval of water is h. below the top of the well. if v is velocity of sound ,then time t after which the splash is heard is equal to
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Answer 1

Answer:

Time taken for thw ball to reach the bottom

= (2h/g)^1/2

Time taken by sound to reach the top

= h/v

Thus total time = (2h/g)^1/2 + h/v

Hope it helps you

Answer 2

Answer:

√(2h/g) + h/v

Explanation:

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Time taken for the ball to reach the bottom

= √(2h/g)

Time taken by sound to reach the top

= h/v

Thus total time = √(2h/g) + h/v