a stone dropped off a height 1 metre after what time it will strike the ground
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Height, s=20m
Initial velocity, u=0
Acceleration due to gravity, g=10 m/s
2
Final velocity, v=?
Time taken, t=?
(i) Using relation,
s=u t+
2
1
gt
2
20=0×t+
2
1
×10×t
2
20=0+5t
2
t
2
=
5
20
=4
t=
4
=2 s
(ii)For a freely falling body:
v
2
=u
2
+2gh
=(0)
2
+2×(10)×(20)
So, v
2
=400
v=
400
=20 m/s
The speed of stone when it hits the ground will be 20m/s.
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