Question

a stone falling freely reaches at ground 5 seconds ,2 seconds after first stone is dropped another stone is dropped. if both reaches at ground together. what is initial separation between them? ​

Answer 1

Answer:

The initial velocity would be greater of the second stone than the first stone.

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Answer 2

Answer:

Explanation:

v=u+at  or v=9.8t

t=  30/10

​  =3.0s is the time at which stone will reach 30 m/s velocity  

First stone will reach s=ut+(1/2)at  2    so s  1 ​   =1/2×10×9m s  1

​   =45m  (initial velocity = u = 0)  

second stone was dropped after 2sec, so time for itt  1

​  =3.0−2.0s=1.0s s  2 ​   =1/2×10×1  2  =5.0m  

so distance between two stones  

D=45.0−5.0=40.400m