Physics, asked by Shhivaa9201, 1 year ago

A stone falls freely from rest from a height h and it travels a distance h/2 in the last second the time of journey

Answers

Answered by akhileshpatil230205
1

Answer:(2+root 2)s

Explanation:

let t: the time of journey

h: displacement inn t seconds

h/2:displacement in last second

h=1/2 gt^2 ....(1)

h/2=1/2g(2t-1)...(2)

1/2*1/2gt^2=1/2g(2t-1)

t^2-4t+2=0

t=2+ root 2 =3.41 sec

t= 2- root 2=0.59 sec

therefore t=(2-root 2 )

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