A stone falls freely from rest from a height h and it travels a distance h/2 in the last second the time of journey
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Answer:(2+root 2)s
Explanation:
let t: the time of journey
h: displacement inn t seconds
h/2:displacement in last second
h=1/2 gt^2 ....(1)
h/2=1/2g(2t-1)...(2)
1/2*1/2gt^2=1/2g(2t-1)
t^2-4t+2=0
t=2+ root 2 =3.41 sec
t= 2- root 2=0.59 sec
therefore t=(2-root 2 )
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