Question

A stone falls freely rest. The distance covered
by it in the last second is equal to
the distance covered by it in the first 2 s. The
time taken by the stone to reach
the ground is​

Answer 1

Answer:

s =ut + 0.5gt

2

_________1

In first 3sec, let it covers distance "d" m.

d=0.5g(3)

2

=4.5g

This distance is same as distance traveled in last second

So, according to formula,

S

n

=u+0.5a(2n−1)

4.5g=0.5g(2n−1)

Here, u=0 and n is number of seconds for which stone is in air.

∴n=5 sec

Substituting in eqn 1,

S= 122.5m

Explanation:

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