Question

A stone falls freely under gravity the total distance covered by it in the last second of its

Answer 1

Answer:

Distance traveled in first 3 seconds -

S= ut + 1/2(a*t^2)

S = 0.5 * 10 * 3^3

S = 45m

Distance traveled in last second = 45m

we know that distance traveled in ‘n’th second = Sn= u + a/2(2n-1)

45 = 0 + 10/2(2*n -1)

solve to get n = 5 seconds.

Therefore total time taken to reach the ground is 5 seconds.

S= ut + 1/2(a*t^2)

S = (0*5) + 1/2(10*5^2)

S = 0 + 1/2(10 * 25)

S = 125

Therefore the height from which the stone is dropped = 125m.

Explanation: