Physics, asked by ridhima2820, 1 year ago

A stone falls from a building and reaches the ground 2.5 later. How high is the building? (g=9.8m/sec2)

Answers

Answered by khanikorjyotipaban
1

Given

u=0m/s

s=?

g=9.8m/s^2

t=2.5s

From Newton's second law

s=ut+1/2gt^2

=0×2.5+1/2×9.8×2.5×2.5

=0+4.9×6.25

=30.625m

Hope it'll help u.

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