A stone falls from a height f 19.6with what velocity does it strke the ground
Answers
Answered by
1
Answer:
19.6 m/s
Explanation:
v = √2gh = √19.6² = 19.6 m/s
Answered by
1
Answer:
19.6 m/s
Explanation:
In the present event a ball is being dropped (the term means that initial velocity=0) from a height h
h = 19.6 m = 2 times the numerical value of g, the acceleration due to gravity
we know how accelerations operate ..it will add per sec the value of g to the velocity
v = g.t
but the time taken to cover h =19.6 m ; using h = (1/2) g . t^2
t = sqrt ( 2.h /g) = 2
so the velocity of striking the ground v = 9.8 m/s^2 x 2 s = 19.6 m/s
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