Question

A stone falls from a height f 19.6with what velocity does it strke the ground​

Answer 1

Answer:

19.6 m/s

Explanation:

v = √2gh = √19.6² = 19.6 m/s

Answer 2

Answer:

19.6 m/s

Explanation:

In the present event a ball is being dropped (the term means that initial velocity=0)  from a height h

h = 19.6 m = 2 times the numerical value of g, the acceleration due to gravity

we know how accelerations operate ..it will add per sec the value of g to the velocity

v = g.t

but the time taken to cover h =19.6 m ; using h = (1/2) g . t^2

t = sqrt ( 2.h /g) = 2

so the velocity of striking the ground v = 9.8 m/s^2 x 2 s = 19.6 m/s