a stone falls from a shift and travels 24.5 in the last second before it reaches the ground at the foot of the shiff find height of the shiff
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u=0m/s.
distance travelled in last second = u+a/2 (2n-1).
n represent in which second last or 1st or 2nd etc.
24.5=0+10/2 (2n-1).
24.5=5 (2n-1).
24.5=10n-5.
24.5+5=10n
29.5 =10n
n= 2.95seconds
3 second ( approx).
means stone has travelled 3 seconds before hitting the ground.
distance travelled in 3 seconds .
s=ut+1/2at^2 (motion formula ).
u=0m/s.
s=1/2×10×(3)^2
s=5×3×3.
s=45m
so the height of the shiff is 45 meter
distance travelled in last second = u+a/2 (2n-1).
n represent in which second last or 1st or 2nd etc.
24.5=0+10/2 (2n-1).
24.5=5 (2n-1).
24.5=10n-5.
24.5+5=10n
29.5 =10n
n= 2.95seconds
3 second ( approx).
means stone has travelled 3 seconds before hitting the ground.
distance travelled in 3 seconds .
s=ut+1/2at^2 (motion formula ).
u=0m/s.
s=1/2×10×(3)^2
s=5×3×3.
s=45m
so the height of the shiff is 45 meter
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