a stone falls from a tall building. Ignoring air resistance and taking g = 10m/s2, what is the velocity after 5 seconds?. how far has the stone fallen after 3 seconds?
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solution:
initial velocity, u= 0m/s
acceleration, a= 10m/s^2
S= ut+1/2at^2
= 0*3+ 1/2*10*9
= 5*9
= 45m
Now, a= v-u/t
= 10= v - 0/5
=> 50= v
velocity after 5 sec is 50m/s.
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initial velocity, u= 0m/s
acceleration, a= 10m/s^2
S= ut+1/2at^2
= 0*3+ 1/2*10*9
= 5*9
= 45m
Now, a= v-u/t
= 10= v - 0/5
=> 50= v
velocity after 5 sec is 50m/s.
__________
hope u like it...☺
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