A stone falls from the top of a building and hits the ground at a speed of 32 m/s. The air resistance-force on the stone is very small and may be neglected.
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Question is incomplete. I think you’re asked to find height of the building.
Use equation of motion
S = (v^2 - u^2)/(2a)
Now, substitute the values
S = (32^2 - 0^2) / (2 × 9.8 m/s^2)
= 52.24 m
Height of the building (= Displacement covered by stone) is 52.24 m
To find time of fall use equation of motion
v = u + at
t = (v - u)/a
= (32 - 0)/9.8
= 3.265 seconds
Use equation of motion
S = (v^2 - u^2)/(2a)
Now, substitute the values
S = (32^2 - 0^2) / (2 × 9.8 m/s^2)
= 52.24 m
Height of the building (= Displacement covered by stone) is 52.24 m
To find time of fall use equation of motion
v = u + at
t = (v - u)/a
= (32 - 0)/9.8
= 3.265 seconds
https://brainly.in/question/194645
Pls help ?
I need to calculate time of Fall ?
Answer edited.
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u=0m/s
v=32m/s
a=g=9.8m/s2
According to the first equation of motion,
v=u+a*t
32=9.8*t
32/9.8=t
t=3.265sec
The final answer is 3.265s.