Question

a stone Falls from the top of a building and travels 53.9 metre in the last second before it reaches the ground find the height of the building​

Answer 1

this should be the answer of your question....

Answer 2

The height of the building​ is 176.4 m.

Explanation:

The initial velocity of the stone, u = 0.

The distance traveled by the stone in the last second before it reaches the ground, h = 53.9 m.

Use the equation of motion as,

$h_t_h=u+\frac{1}{2} g(2t-1)$.

substitute the values, we get

$53.9=0+\frac{9.8m/s^2}{2}(2t-1)$

2t-1 =11

t = 6 s.

Now use the second equation of motion as,

$s=ut+\frac{1}{2}gt^2$

substitute the values, we get

$s=0+0.5\times9.8\times(6)^2$

s = 176.4 m.

Thus, the height of the building​ is 176.4 m.

#Learn More: equation of motion.

https://brainly.in/question/11507922