A stone falls from the top of tower in 8 sec . How much it take to cover the first quarter of the distance starting from the top
Answers
QUESTION:
A stone falls from the top of tower in 8 sec . How much it take to cover the first quarter of the distance starting from the top.
ANSWER:
to cover the first quarter of the distance starting from the top = 4 seconds
Explanation:
given that,
A stone falls from the top of tower in 8 sec .
here,
we have,
initial velocity of Stone = 0
[it was at rest]
time taken in Falling = 8 seconds
let the height of tower be h
now,
we have,
initial velocity(u) = 0 m/s
gravitational acceleration(g) = 10 m/s²
time taken = 8 seconds
height of the tower = h
now,
by the equation of gravitation
h = ut + 1/2(gt²)
putting the values,
h = 0(8) + 1/2(10)(8)²
h = 0 + 320
h = 320 m
now,
first quarter of the distance starting from the top
= 320/4
= 80 m
time taken to cover 1st quarter from the top
here,
height(h) = 80 m
initial velocity = 0
gravitational acceleration = 10 m/s²
by the equation of gravitation
h = ut + 1/2(gt²)
putting the values,
80 = (0)t + 1/2(10)t²
5t² + 0 = 80
5t² = 80
t² = 80/5
t² = 16
t = √16
t = 4
so,
time taken to cover first quarter from the top of the tower
= 4 seconds
HeRe Is Your Ans ⤵
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Ans :-
➡4 Sec
Solution :-
Time taken = 8 sec
Initial velocity = 0 m/s
Acceleration = 10 m/s²
Therefore distance covered ,
➡s = ut + 1/2 at²
➡s = 0 × 8 + 1/2 × 10 × 8²
➡s = 5 × 64
➡s = 320 meter
Therefore distance covered in the 1st quarter Is 320 / 4 = 80 m
Distance = 80 meter
Acceleration = 10 m/s
Initial velocity = 0 m/s
Therefore time taken ,
➡s = ut + 1/2 × at²
➡80 = 0 × t +1/2 × 10 × t²
➡80 = 5t²
➡80 / 5 = t²
➡t² = 16 =
➡t = √16
➡t = 4
Therefore , time taken to travel the 1st quarter ( 80 meter ) = 4 seconds
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