Question

A stone falls from the top of tower in 8 sec . How much it take to cover the first quarter of the distance starting from the top

Answer 1

QUESTION:

A stone falls from the top of tower in 8 sec . How much it take to cover the first quarter of the distance starting from the top.

ANSWER:

to cover the first quarter of the distance starting from the top = 4 seconds

Explanation:

given that,

A stone falls from the top of tower in 8 sec .

here,

we have,

initial velocity of Stone = 0

[it was at rest]

time taken in Falling = 8 seconds

let the height of tower be h

now,

we have,

initial velocity(u) = 0 m/s

gravitational acceleration(g) = 10 m/s²

time taken = 8 seconds

height of the tower = h

now,

by the equation of gravitation

h = ut + 1/2(gt²)

putting the values,

h = 0(8) + 1/2(10)(8)²

h = 0 + 320

h = 320 m

now,

first quarter of the distance starting from the top

= 320/4

= 80 m

time taken to cover 1st quarter from the top

here,

height(h) = 80 m

initial velocity = 0

gravitational acceleration = 10 m/s²

by the equation of gravitation

h = ut + 1/2(gt²)

putting the values,

80 = (0)t + 1/2(10)t²

5t² + 0 = 80

5t² = 80

t² = 80/5

t² = 16

t = √16

t = 4

so,

time taken to cover first quarter from the top of the tower

= 4 seconds

Answer 2

HeRe Is Your Ans ⤵

*****

Ans :-

➡4 Sec

Solution :-

Time taken = 8 sec

Initial velocity = 0 m/s

Acceleration = 10 m/s²

Therefore distance covered ,

➡s = ut + 1/2 at²

➡s = 0 × 8 + 1/2 × 10 × 8²

➡s = 5 × 64

➡s = 320 meter

Therefore distance covered in the 1st quarter Is 320 / 4 = 80 m

Distance = 80 meter

Acceleration = 10 m/s

Initial velocity = 0 m/s

Therefore time taken ,

➡s = ut + 1/2 × at²

➡80 = 0 × t +1/2 × 10 × t²

➡80 = 5t²

➡80 / 5 = t²

➡t² = 16 =

➡t = √16

➡t = 4

Therefore , time taken to travel the 1st quarter ( 80 meter ) = 4 seconds

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