Question

A stone falls past a window 2.45m high in half a second. From what height from the top of the window is it falling

Answer 1

First we get speed at point B then we take it as v in newton's 3rd equation of motion. Now using 3rd law we get value of s. Hope it helps. .

Answer 2

Answer:

0.288m

Explanation:

Given:

S=2.45m

t=0.5 sec

To find:

Height from the window

Solution:

The third law of Newton states that every action has a corresponding and opposing reaction. In a collision, two bodies exert forces on one another that are both strong and pointed in the wrong direction.

Newton's second law states that the acceleration of an object due to a net force is inversely proportional to the mass of the object, directly proportional to the amount of the force, and travelling in the same direction as the force.

To arrive at the third law of motion equation, we use both motion equations.

$S = ut + \frac{1}{2} at^{2} \\v^{2} =u^{2} +2as$

Now substituting the given value in the equation

$S = ut + \frac{1}{2} at^{2} \\2.45=u(0.5)+\frac{1}{2} (10)(0.25)\\2.45-1.25=0.5u\\1..2=0.5u\\u=\frac{1.2}{0.5} \\u=2.4m/s$

We obtain velocity on top of the window using the aforesaid approach. However, its initial velocity decreased when dropped from a height above the window.

u=0 and v=2.4

$v^{2} =u^{2} +2as\\s=\frac{v^{2} }{2a} \\=\frac{(2.4)(2.4)}{(2)(10)} \\=0.288m$

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