Question

A stone fell from a 45-m high cliff and hit the ground. What is the final velocity with which it hits the ground?​

Answer 1

Answer:

The final velocity with which it hits the ground is 30 m/s

Explanation:

Distance covered by the stone = h = 45 m

Initial velocity of stone = u = 0 m/s  ( because stone is at rest )

Acceleration due to gravity = g = 10 m/s²

Using the equation v² - u² = 2gh, we have

   v² - u² = 2gh

   v² - (0)² = 2 × 10 × 45

   v² = 900

   v = √900

∴  v = 30 m/s

Hence, the final velocity with which it hits the ground is 30 m/s.