Question

A stone fell from the top of a tower taking 5 seconds to reach the ground level calculate.
(i) The velocity of the stone on reaching the ground.
(ii) The height of the tower (g = 9.8 m/s2).

Answer 1

Answer:see file

Explanation:

Answer 2

Explanation:

It is given that,

A stone fell from the top of a tower taking 5 seconds to reach the ground level. The initial velocity of the stone is equal to 0. Let v is the velocity of the stone on reaching the ground. It can be given by :

(i) $v=u+at$

Here, a = g

$v=gt\\\\v=9.8\times 5\\\\v=49\ m/s$

(ii) Let h is the height of the tower. It can be calculated by :

$h=ut+\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times 5^2\\\\h=122.5\ m$

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Kinematics

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