Question

A stone free fall from rest. the distance covered by it in the last secound is equal to the distance covered by it in the first three secound the take time by the stone to reach the ground is
A 4s B 5s C 8s d 10s

with explenation​

Answer 1

Answer:

Let the time for which it remained in air be t.

Initial velocity of stone u=0 m/s

Distance covered in first 5 second, S=ut+

2

1

gt

2

where t=5 s

∴ S=0+

2

1

×10×5

2

=125 m

Distance covered by stone in last second of motion S

′

=S

t

−S

t−1

OR S

′

=ut+

2

1

gt

2

−[u(t−1)+

2

1

g(t−1)

2

] where u=0

OR S

′

=

2

1

g[t

2

−(t−1)

2

]

⟹ S

′

=

2

1

g(2t−1)

But S

′

=S

2

1

×10(2t−1)=125

We get 2t−1=25

⟹ t=13s

Explanation:

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Answer 2

Answer:

In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.