Question

A stone having weight 5kgf is kept the roof of a building of height 50m.Calculate the amount of energy stored in the body.[take:1kgf=1N]
any please help me​

Answer 1

Given:-

• Force = 50 ( As it is given 1 kgf = 10N)

• Height ,h = 50 m

To Find:-

• Potential Energy ,PE

Solution:-

As we know that the energy possess by body due to its position is called Potential Energy.

•PE = mgh

As mg is the Force (F)

• PE = F×h

where,

PE is Potential Energy

F is the force

h is the height

Substitute the value we get

→ PE = 50 × 50

→ PE = 2500 J

Therefore,the energy stored in the body is 2500 Joules.

Answer 2

Answer:

2450 joule

Explanation:

a stone is kept at height of 50m it means that it should posses potential energy.

To calculate potential energy formula is- mgh

Here,mass=5kgf or 5N , g=9.8 , height=50m.

so, 5×9.8×50=2450